How do a(t), v(t), and x(t) relate in physics equations?

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The discussion focuses on the relationships between acceleration a(t), velocity v(t), and position x(t) in physics equations. The correct equations are established as a(t) = dv/dt and v(t) = dx/dt. The user initially proposed incorrect formulas for v(t) and x(t) but was guided to the correct integration process, leading to the final position equation x(t) = (α/6)t^3 + wt + (A - 4/3α - 2w). This highlights the importance of correctly applying calculus to derive motion equations.

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a(t)=dv/dt
v(t)=dx/dt




I thought it was just
v(t)= (alpha)t^2/2 + w
x(t)=((alpha)t^2)/6 + wt + a


But the answer is ((alpha)t^2)/6 + wt + a - 2w - 4(alpha)/3

Can someone please explain this to me...
 
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Starting from your v = .5*@*t^2/2 + W
x is the integral dt of this: x = .5*@/3*t^3 + wt + k
To evaluate the constant k, put in time 2 and x = A:
This gives you k = A - 4/3@ - 2w
Put that back in the x formula and you have the answer you are looking for, though there seems to be a t^2 instead of a t^3 in the answer.
 
Thank you very much!
 

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