How do atoms emit different photon energies?

AI Thread Summary
Atoms emit different photon energies based on the specific energy levels of their electrons. In hydrogen, when an electron absorbs a photon, it jumps to a higher energy orbital, and when it emits a photon, it falls back to a lower orbital. The lengths of the arrows in diagrams represent the energy difference between these orbitals. For further understanding, searching "photon emission from hydrogen" can provide useful resources. The discussion concludes with no additional points to address.
Jeff97
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Summary:: Based on this diagram can someone explain how atom of hydrogen gas can be made to emit photons of different energies?

IMG_3303.jpg
 

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This homework ? If so, then post in introductory physics HW forum and tell us what you know and did to come to an answer...
 
BvU said:
This homework ? If so, then post in introductory physics HW forum and tell us what you know and did to come to an answer...
No homework here just wanted an explanation
 
  • Skeptical
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well, what about the lengths of the arrows ? Are they all the same ?
What do they represent ?

and what does img_3305 have to do with this at all ?
 
Last edited:
Jeff97 said:
No homework here just wanted an explanation
Nevertheless: tell us what you know and did to come to an answer...
 
So, I typed "photon emission from hydrogen" into google and got some pretty useful links. Have you tried that? If you find something there that confuses you, then this maybe a good place to ask for clarification.
 
Short answer is there are specific atomic orbitals where the hydrogen electron may reside. As the electron absorbs a photon of a specific frequency it will jump to a higher orbital. When the electron emits a photon it will drop to a lower orbital.

http://hyperphysics.phy-astr.gsu.edu/hbase/hyde.html

Closing this thread since there’s nothing more to say on the topic.
 
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