How Do Field Axioms Prove Properties of Complex Number Inverses?

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SUMMARY

This discussion focuses on proving properties of complex number inverses using field axioms. The two properties to be proven are: (a) 1/(z1z2) = (1/z1)(1/z2) and (b) (1/z1) + (1/z2) = (z1 + z2)/(z1z2). The axioms of a field, specifically associativity and commutativity for addition and multiplication, are essential for these proofs. The discussion emphasizes the importance of the definition of "multiplicative inverse" and clarifies the correct formulation of the second equation.

PREREQUISITES
  • Understanding of field axioms, specifically associativity and commutativity.
  • Knowledge of the definition of multiplicative inverse.
  • Familiarity with complex numbers and their properties.
  • Basic algebraic manipulation skills.
NEXT STEPS
  • Study formal proofs in abstract algebra, focusing on field theory.
  • Explore the properties of complex numbers and their inverses in detail.
  • Learn about algebraic structures and their axioms beyond fields.
  • Practice proving identities involving multiplicative inverses in various mathematical contexts.
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Students studying abstract algebra, mathematicians interested in field theory, and anyone looking to deepen their understanding of complex number properties and formal proofs.

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Homework Statement



Using only the axioms for a field, give a formal proof for the following:

a) 1/z1z2 = 1/z1 1/z2
b) 1/z1 + 1/z2 = z1 + z2/z1z2


The Attempt at a Solution



I really am having a tough time understanding this problem. I know the axioms of a field

i.e. associativity and commutativity for addition and multiplications (those are the only axioms she cares about) but how do i use these to show the above is true?
 
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Well, obviously in addition to associativity and commutatitivity you will need to use the definition of "mutliplicative inverse" since that is what 1/z is. And, just as obviously each of these should have the provision "z1 and z2 not equal to 0". And you are missing parentheses from (b)- it should be 1/z1+ 1/z2= (z1+ z2)/z1z2, not what you have.

For the first one, the left side is the multiplicative inverse of z1z2. To show that the right side is also, you need to show that (z1z2)(1/z1)(1/z2)= 1.

For the second you want to show that (1/z1+ 1/z2)[(z1+ z2)/z1z2]= 1.
 

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