How Do Free Electrons Transfer Kinetic Energy in Copper Wires?

AI Thread Summary
Free electrons in copper wires transfer kinetic energy to the wire's atoms primarily through collisions, which increase atomic vibrations and generate heat. These electrons are not bound to individual atoms but exist in a "sea" around the metal's atomic structure. When an electric field accelerates these free electrons, they collide with the metal ions, leading to energy transfer and heating of the conductor. The discussion also touches on the distinction between classical and quantum mechanical models, with the latter involving electron-phonon scattering to explain resistivity and heating. Simplifying quantum mechanics for educational purposes remains a challenge.
cubozoan
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Hi forum

I need to explain the following to pupils of about 17 years of age.

2 questions regarding free electron kinetic energy transfer to copper wire (or resistor) material atoms in an electrical circuit.

1. I am confused as in which situation free electrons in a circuit transfer energy to heat a copper wire. Is it electrons that are free of their atom or electrons that jump to other outer valence bands of (copper wire) atoms?

2. How do free electrons actually transfer energy (kinetic) to (copper wire) atoms? How do they vibrate the copper wire atoms to heat the wire? Do they collide or some other mechanism?

Thank you for your time reading this. I hope I have made myself clear

Regards

Andy
 
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cubozoan said:
1. I am confused as in which situation free electrons in a circuit transfer energy to heat a copper wire. Is it electrons that are free of their atom or electrons that jump to other outer valence bands of (copper wire) atoms?

The free electrons are not bound to any single atom, but are instead bound to the metal as a whole. You can think about it as having each metal atom rigidly set in place with a "sea" of free electrons around it. See here: http://en.wikipedia.org/wiki/Electric_current#Metals

2. How do free electrons actually transfer energy (kinetic) to (copper wire) atoms? How do they vibrate the copper wire atoms to heat the wire? Do they collide or some other mechanism?

Collisions with the ions.
 
Thank you for the replies and discussion. I feel some of the content is beyond my understanding.

I think my first question has been answred - they are both a similar thing. In both situations they still belong to a nucleus.

I need help describing how electrons (or a sea of electrons) transfer kinetic energy (being accelerated by electric field within an electrical circuit) to conductor atoms - thus heating conductor and electrons losing kinetic energy themselves
 
As soon as I posted a reply it seems some previous posts have vanished
 
cubozoan said:
I think my first question has been answred - they are both a similar thing. In both situations they still belong to a nucleus.

A free electron cannot be said to belong to anyone nucleus. They are being shared between every nucleus in the metal.

I need help describing how electrons (or a sea of electrons) transfer kinetic energy (being accelerated by electric field within an electrical circuit) to conductor atoms - thus heating conductor and electrons losing kinetic energy themselves

Was the explanation that they collide with ions not good enough?
 
In the relatively simple Drude model, the conduction electrons are treated as classical particles that can collide with the atomic cores. If the electrons are accelerated by an electrical field, the collisions increase the vibration of the atoms and cause heating. See http://en.wikipedia.org/wiki/Drude_model .

In a quantum mechanical treatment, electrons are not seen as classical particles and we talk about electron-phonon scattering as the source of electrical resistivity and heating.
 
Thank you guys. I wonder if it seems possible to explain QM situation simply?

There is a challenge
 
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