How Do HCl, Aniline, Sodium Nitrite, and Beta-Naphthol React?

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The discussion centers on a diazotization reaction involving HCl, aniline, sodium nitrite, and beta-naphthol. The process begins with the formation of a diazonium salt from aniline and sodium nitrite, which is then reacted with beta-naphthol in a basic solution. The resulting red precipitate indicates the formation of an azo dye, a common outcome when diazonium salts react with phenolic compounds. The necessity for low temperatures during the reaction is emphasized to stabilize the diazonium salt and prevent decomposition. Overall, the chemistry involved is recognized as significant and interesting.
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Homework Statement



Hey, so I've done a basic test for an amine, which involves mixing HCl and aniline and cooling it, cooling a solution of sodium nitrite in a second test tube, and mixing the two when sufficiently cold. When both soutions reached zero celsius, they were mixed, and a solution if beta-naphthol in NaOH was added. Could anyone tell me how everything's reacted?

Homework Equations



Been given nothing... after all, that's what I'm supposed to find out

The Attempt at a Solution



A red precipitate was formed, which at a wild and irrational guess could be based from the beta-naphthol, but I honestly have no idea where to start with this one. I haven't been able to find out what it could be anywhere...

Any help whatsoever would be greatly appreciated :)

EDIT: And why would the solutions need to be so cold? It's kinda counter-intuitive by my thinking... not a homework question, this.
 
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The reaction you are asking about is a diazotization reaction. The initially formed diazonium salt of aniline is reacted with an aromatic alcohol to produce a diazo compound. Aromatic diazonium salts that react with phenols generally produce highly colored compounds (azo dyes).

It's goooood chemistry!
 
Thank you very much! :)
 
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