How do I calculate acceleration and magnitude in physics?

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To calculate acceleration, use the formula a = (final velocity - initial velocity) / time, which measures the change in velocity over time. Magnitude refers to the size or length of a vector, distinguishing it from speed, which lacks direction. In one-dimensional problems, magnitude can be viewed as the absolute value of a vector. Acceleration occurs whenever there is a change in speed or direction; constant speed in a straight line indicates no acceleration. Understanding these concepts is crucial for mastering basic physics principles.
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New at Physics, PLEASE HELP :)

Hello, I'm in 8th grade advanced Science, we just started physics but I'm very confused. Can anybody help me on how to calculate acceleration and magnitude? Thanks :approve: This is NOT homework, I am just trying to study for an exam tomorrow.
 
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Well magnitude is a general property of vectors. Not just acceleration.
For example. velocity is a vector, the difference between "velocity" and "speed" is that "velocity" has a magnitude and a direction, whereas "speed" only has magnitude.

So "magnitude" is like the length of the vector. Another way to look at is is that if you are doing 1-dimensional problems (which you probably are) then your "vectors" are basically just a single number that can be positive or negative, then "magnitude" is like the absolute value.As for acceleration, just think of it as the change in velocity over time.
a=\frac{\Delta v}{\Delta t}=\frac{v_{f}-v_{i}}{\Delta t}
 


Hello :)

Acceleration is a rate of change of velocity, where velocity is a rate of change of position.

If I run in a 100m race, and finish in 10 seconds, my velocity is how fast I go from beginning to end. In this case it is:

v = \frac{finish-start}{time} = 10m/s

In this case, the start is the x=0 position, and finish is the x=100 position.

Acceleration is similar to this.

If I start by going 5m/s and end at 15m/s, then my acceleration is:

a = \frac{final velocity - initial velocity}{time} = \frac{15m/s-5m/s}{10s} = 1m/s^2

Now, all of these are averages for the given example, and I randomly chose numbers.

Also, these are all magnitudes. If I were to attach a direction to the magnitude, it would become a vector.

Hope this helps.
 


While a body is undergoing a change in speed, or even just a change in direction, then it is accelerating (or decelerating).

Only if it is traveling at a constant speed AND in a straight line is it NOT accelerating.

Something going around and around on a circular path at a constant speed is constantly accelerating, since for no time interval is it seen to be traveling in a straight line.
 
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