How do I Calculate GMm with Given a and T for Gravitation Problem?

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To calculate GMm given the semi-major axis (a) and the orbital period (T) in a gravitation problem, Kepler's third law can be applied, which states that a^3/T^2 is a constant. The user successfully derived part A and part B of the problem, with part A yielding 1.27 x 10^17/r^2 and part B resulting in 1.9 x 10^27. By assuming a equals r and ignoring eccentricity, GM can be calculated. The focus is on determining the mass of Jupiter, as it is significantly greater than the mass of its moons. The discussion concludes with the user confirming they have solved the problem.
Clara Chung
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Homework Statement


The question is attached

Homework Equations


Kepler's laws and gravitational equations

The Attempt at a Solution


the question gave me a and T, I related it with Kepler's third law a^3/T^2, then I don't know what to do next. The answer of part a is 1.27 x10^17 /r^2 , part b = 1.9 x 10^27, How can I find GMm as the question only provided a and T?
 

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What did you get out of Keplers third law ?
 
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BvU said:
What did you get out of Keplers third law ?
If I assume a=r, I can get GM?
 
I think you can ignore the excentricity, yes.
 
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BvU said:
I think you can ignore the excentricity, yes.
How can I get m after that?
 
Kepler's third law says a^3/T^2 is 'constant', namely ...
(They only ask for M of Jupiter and that's >> m of moons)
 
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BvU said:
Kepler's third law says a^3/T^2 is 'constant', namely ...
(They only ask for M of Jupiter and that's >> m of moons)
Thanks I got part A and B
 
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