How do I calculate the length of a rod?

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To calculate the breaking point of a steel rod, the tensile strength, which is 500 MPa, represents the maximum stress the material can withstand before fracturing. The length of the rod is given as 406700, but units should be clarified for accurate calculations. The problem's vagueness regarding the rod's positioning and context in a tensile testing machine complicates the solution. Understanding the stress-strain curve is crucial, as the tensile strength indicates the point before fracture, while the material behaves ductilely, bending before breaking. Accurate calculations require clear data and context about the rod's situation during testing.
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Homework Statement



I need to calculate the breaking point of a Steel rod.

Homework Equations



I know the density: 8.03
Cross section: 1m^2
Tensile Strength: 500*10^6
Volume: 62266500.6
The whole length is: 406700


The Attempt at a Solution


Please provide me with explanations and equations which i could use. Thank You.
 
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You must attempt a solution before we will help. Furthermore, your problem is vague. How is the rod situated?
 
LawrenceC said:
You must attempt a solution before we will help. Furthermore, your problem is vague. How is the rod situated?
I don't have an attempt at a solution because i don't really know what to do at all. There is no information given except for what i wrote above, that's why i have a big problem with solving this..
 
Material Science right?

You seem to be asking two questions the length of the rod and the breaking point of the steel correct?

If you are wondering about the breaking point of the steel it is a trick question the tensile strength is the maximum stress that may be sustained by a structure in tension (it is the top point in the stress/strain curve). If this stress is applied and maintained fracture will result.

so the tensile strength is the breaking point of steel.

As for the length of the rod, you have the whole length written up there as 406700. Units would help with all your data.

I have a few formulas that would work for this problem but with your given information it looks like a 100% trick problem.

LawrenceC said:
Furthermore, your problem is vague. How is the rod situated?

It would be placed in a tensile testing machine, (most if not all of the time vertical) with two crossheads to attach the specimen.
 
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Hi
I have attached a pic i found of stress strain curve of mild steel,
Here, the breaking point's stress is given less that maximum stress ...

EDIT: Forgot to add pic ...

http://pages.uoregon.edu/struct/courseware/461/461_lectures/461_lecture24/461_lecture24_pic1.gif
 
Last edited by a moderator:
cupid.callin said:
Hi
I have attached a pic i found of stress strain curve of mild steel,
Here, the breaking point's stress is given less that maximum stress ...

EDIT: Forgot to add pic ...

If you were to give me that value of stress and I were to look at the chart I would still be at the left side of the curve. How did you get to the right side of the curve?

The tensile strength is the breaking point, unless the problem has a chart along with it with time through the experiment with the corresponding stress on the specimen. This is the answer they are looking for.

As an engineer if your design reaches the tensile strength is a broken plastic deformed mess.

You understand that the slope reaches a max (tensile strength) and then begins to slope down, because the steel has already fractured. Metals are a ductile material though they do not crack into two like a brittle ceramic dinning room plate would. It bends first and the fracture grows, until the fracture is complete and it is in two pieces.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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