How do I get this equation for period?

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The equation for the period of a physical pendulum is T = 2π√(I/mgL), where T represents the period, I is the moment of inertia, m is the mass, g is the acceleration due to gravity, and L is the distance from the pivot to the center of mass. The confusion arises from the factor of 2 in the equation, which is essential for accurately calculating the period of a rod-like object swinging as a pendulum. Understanding the derivation of this equation requires knowledge of rotational dynamics and the physical properties of pendulums.

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frasifrasi
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In class, we were asked to the relation T =2π√(2I/mgL).

However, I am only able to get T =2π√(I/mgL) -- I have no idea where that 2 came from. This is for a physical pendulum of a rod like object swinging back and forth.

Does anyone know how to get that equation?
 
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From what I know, you are right that T = 2\pi \sqrt{\frac{I}{mgL}}

I don't know where that extra 2 came from either.
 
It would have helped a lot if you had used the template. What exactly is the problem to be solved here? About what point is the inertia measured? What work have you done to arrive at a solution?
 

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