How do I simplify equations with ln(x + a)?

[Rionoer]

Hi,

I have a problem solving equations involving for example: ln((e^x)+1) = ln(e^x) + 1
How do I simplify this expression, or any expression involving ln(x + a)

 

[statdad]

If you rewrite the first equation as

<br /> \ln{(e^x+1)} - \ln{e^x} = 1 <br />

you can use properties of logarithms to simplify the left side. Once that's done you should be able to proceed.

 

[Rionoer]

Thanks, it helped!