How do I sketch a direction field for Newton's 2nd law with a constant added?

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Homework Help Overview

The discussion revolves around sketching a direction field related to Newton's second law with an added constant. The original poster expresses confusion about the concept of direction fields and how to apply it to the given equation involving velocity and time.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand how to represent the equation dv/dt = -g + k/m as a direction field but struggles with the concept of plotting it. Some participants suggest relating the problem to the general form of a direction field, while others question the understanding of slope in this context.

Discussion Status

The discussion is ongoing, with participants exploring the meaning of slope and its application to the problem. There is a mix of attempts to clarify the concept of direction fields and the original poster's uncertainty about graphing the equation.

Contextual Notes

The original poster mentions having notes that are unclear and expresses a lack of confidence in graphing, indicating potential gaps in understanding the foundational concepts necessary for this problem.

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Homework Statement



(i'm not sure if this is the correct forum please move it if incorrect)
my problem is with generally drawing direction fields - i don't really know what to do. i have notes but i can't make head nor tail of them. this is an example of a question concerning them:

veloc.png


Homework Equations



i know that if you stick the requirments into Newton's 2nd law adding constant k you get that equation, and i know to find the terminal velocity you integrate and find v, but i don't know how to sketch the direction field.

The Attempt at a Solution



i see that

dv/dt = -g + k/m

but this seems to be independent of both v and t so how do i plot it as a graph?

even if there were a v or t in that equation i still wouldn't be comfortable to draw the direction field because i don't know what to do >_>;

thanks
 
Last edited:
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Think of direction fields as a [tex]{dy \over dx} = f(x,y)[/tex]. At each point [tex](x,y)[/tex] on the graph, you draw a tic-mark with slope equal to f(x,y). So here, instead of x and y, we have v and t, and f(v,t)=-g+k/m. What's the slope of each tick mark going to be?
 
uhh
i'm not sure...some kind of straight line?
 
Check the meaning of the word "slope". It is a number not "some kind of line". What does the slope of a line mean?
 
ok i looked up slope and now know it is a number but the answer to this question still eludes me!

i don't know how you'd put the equation on a graph

the notes i have for this involve looking at the independence of say, x of the equation so I am rather stumped. also i just suck at graphs...
 
Last edited:

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