How do I solve this physics exercise (Equilibrium)?

Click For Summary
The discussion revolves around solving a physics exercise related to equilibrium involving cable tensions. The participant calculates that the 500-pound vertical load is supported entirely by cable CD, with 375 pounds distributed horizontally to the other two cables. Each of these cables, being symmetric, carries 187.5 pounds horizontally. Another participant confirms the calculations, arriving at a slightly different value of 197.64 pounds, suggesting minor discrepancies may be due to rounding. The consensus indicates that the original approach is largely correct, with only minor adjustments needed for precision.
Tapias5000
Messages
46
Reaction score
10
Homework Statement
Determine the force required on each cable to sustain the load of 500lb
Relevant Equations
Σfx=0, Σfy=0, Σfz=0
1632608403797.png

I tried to solve it and I got the following, is it correct?
aa.png
 
Physics news on Phys.org
Looks ok.

Insofar as 2 of the cables are in the horizontal plane, then the 500 pound vertical load must all be carried by the vertical comp of cable CD. And with that 3-4-5 triangle, 3 fourths of it or 375 pounds , must go horizontally to the other 2 cables, and their being symmetric, that’s half again or 187.5 borizontally to each, or cable tension root 10/3 times that. Saves a few lines. At least on this one.
 
PhanthomJay said:
Looks ok.

Insofar as 2 of the cables are in the horizontal plane, then the 500 pound vertical load must all be carried by the vertical comp of cable CD. And with that 3-4-5 triangle, 3 fourths of it or 375 pounds , must go horizontally to the other 2 cables, and their being symmetric, that’s half again or 187.5 borizontally to each, or cable tension root 10/3 times that. Saves a few lines. At least on this one.
Are my answers correct?
 
Tapias5000 said:
Are my answers correct?
Near enough. I get 197.64...
 
haruspex said:
Near enough. I get 197.64...
ooh... maybe then only decimals are involved in the procedure... well I'll settle for that
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

Similar threads

Replies
4
Views
2K
  • · Replies 58 ·
2
Replies
58
Views
2K
Replies
10
Views
799
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
943
  • · Replies 7 ·
Replies
7
Views
4K
Replies
6
Views
2K
Replies
2
Views
691
  • · Replies 8 ·
Replies
8
Views
1K
Replies
11
Views
3K