How do I solve this physics exercise (Equilibrium)?

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SUMMARY

The discussion focuses on solving a physics exercise related to equilibrium involving cable tensions and load distribution. The participant calculates that a 500-pound vertical load is supported by cable CD, with 375 pounds distributed horizontally to two other cables due to symmetry. The final tension in each cable is determined to be approximately 197.64 pounds. The calculations utilize the principles of a 3-4-5 triangle to simplify the problem.

PREREQUISITES
  • Understanding of static equilibrium in physics
  • Knowledge of vector components in force analysis
  • Familiarity with the properties of right triangles, specifically the 3-4-5 triangle
  • Basic proficiency in algebra for solving equations
NEXT STEPS
  • Study the principles of static equilibrium in physics
  • Learn about vector decomposition and force analysis techniques
  • Explore advanced applications of the 3-4-5 triangle in engineering problems
  • Practice solving similar equilibrium problems with varying loads and configurations
USEFUL FOR

This discussion is beneficial for physics students, engineering students, and professionals involved in structural analysis or mechanics who are looking to enhance their understanding of equilibrium and cable tension calculations.

Tapias5000
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Homework Statement
Determine the force required on each cable to sustain the load of 500lb
Relevant Equations
Σfx=0, Σfy=0, Σfz=0
1632608403797.png

I tried to solve it and I got the following, is it correct?
aa.png
 
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Looks ok.

Insofar as 2 of the cables are in the horizontal plane, then the 500 pound vertical load must all be carried by the vertical comp of cable CD. And with that 3-4-5 triangle, 3 fourths of it or 375 pounds , must go horizontally to the other 2 cables, and their being symmetric, that’s half again or 187.5 borizontally to each, or cable tension root 10/3 times that. Saves a few lines. At least on this one.
 
PhanthomJay said:
Looks ok.

Insofar as 2 of the cables are in the horizontal plane, then the 500 pound vertical load must all be carried by the vertical comp of cable CD. And with that 3-4-5 triangle, 3 fourths of it or 375 pounds , must go horizontally to the other 2 cables, and their being symmetric, that’s half again or 187.5 borizontally to each, or cable tension root 10/3 times that. Saves a few lines. At least on this one.
Are my answers correct?
 
Tapias5000 said:
Are my answers correct?
Near enough. I get 197.64...
 
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haruspex said:
Near enough. I get 197.64...
ooh... maybe then only decimals are involved in the procedure... well I'll settle for that
 

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