How do I solve this physics exercise (Equilibrium)?

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Homework Help Overview

The discussion revolves around a physics exercise related to equilibrium, specifically involving cable tensions and load distribution in a system with vertical and horizontal components.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the distribution of a vertical load among cables, referencing geometric relationships such as a 3-4-5 triangle. Questions about the correctness of calculations and interpretations of tension in the cables are raised.

Discussion Status

Some participants express tentative agreement with calculations, while others provide alternative numerical results, indicating ongoing exploration of the problem. There is a focus on verifying the accuracy of the answers without reaching a definitive conclusion.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available and the methods they can use to solve the problem.

Tapias5000
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Homework Statement
Determine the force required on each cable to sustain the load of 500lb
Relevant Equations
Σfx=0, Σfy=0, Σfz=0
1632608403797.png

I tried to solve it and I got the following, is it correct?
aa.png
 
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Looks ok.

Insofar as 2 of the cables are in the horizontal plane, then the 500 pound vertical load must all be carried by the vertical comp of cable CD. And with that 3-4-5 triangle, 3 fourths of it or 375 pounds , must go horizontally to the other 2 cables, and their being symmetric, that’s half again or 187.5 borizontally to each, or cable tension root 10/3 times that. Saves a few lines. At least on this one.
 
PhanthomJay said:
Looks ok.

Insofar as 2 of the cables are in the horizontal plane, then the 500 pound vertical load must all be carried by the vertical comp of cable CD. And with that 3-4-5 triangle, 3 fourths of it or 375 pounds , must go horizontally to the other 2 cables, and their being symmetric, that’s half again or 187.5 borizontally to each, or cable tension root 10/3 times that. Saves a few lines. At least on this one.
Are my answers correct?
 
Tapias5000 said:
Are my answers correct?
Near enough. I get 197.64...
 
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haruspex said:
Near enough. I get 197.64...
ooh... maybe then only decimals are involved in the procedure... well I'll settle for that
 

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