Engineering How do I start this problem? (diode circuit)

[rude man]

Would it go from 0 to 0.7 or -0.7 to 0.7? I really don't understand the problem(s) and neither do any of my classmates.

The thing you need to see is that the diodes are "not there" if V_o is between - 0.7V and + 0.7V. So for that range of V_o you get just the sinusoidal output voltage 1.414sin(wt). But as soon as Vo > +0.7V or < -0.7V, Vo has to stay ("is clamped") at those voltage levels. Now try to reconstruct what V_o must look like over an entire period.

 

[cnh1995]

If there is no series resistor in my problem (it is parallel), does that mean there is no clipping in my problem?

Yes. There is no clipping.

Can you explain this?

Say your input is 1V rms. If the diode is maintaining 0.7V across it, where is the remaining voltage? It has to appear across the series resistance. That means, without the series resistance, all the voltage would appear across the diodes and there will be no clipping. If there is a series resistance, the diode almost maintains 0.7V across it and the remaining voltage appears across the series resistance.

 

[servehover]

The thing you need to see is that the diodes are "not there" if V_o is between - 0.7V and + 0.7V. So for that range of V_o you get just the sinusoidal output voltage 1.414sin(wt). But as soon as Vo > +0.7V or < -0.7V, Vo has to stay ("is clamped") at those voltage levels. Now try to reconstruct what V_o must look like over an entire period.

So it'd basically be a sine wave that is cut off beyond 0.7 and -0.7.
If this question is a trick question, the answer would simply be Vo = 1Vrms right?

 

[servehover]

Yes. There is no clipping.

Say your input is 1V rms. If the diode is maintaining 0.7V across it, where is the remaining voltage? It has to appear across the series resistance. That means, without the series resistance, all the voltage would appear across the diodes and there will be no clipping. If there is a series resistance, the diode almost maintains 0.7V across it and the remaining voltage appears across the series resistance.

So just to be confirm:
There is no series resistor in my circuit (it looks parallel). This means that the output voltage is simply 1Vrms...?

 

[cnh1995]

So just to be confirm:
There is no series resistor in my circuit (it looks parallel). This means that the output voltage is simply 1Vrms...?

I would say yes..

 

[servehover]

I would say yes..

I think I will stick to 1Vrms as I have yet to find any clipping circuit on Google with parallel resistor. Can you offer any hints for the other 3 problems?

 

[NascentOxygen]

So just to be confirm:
There is no series resistor in my circuit (it looks parallel). This means that the output voltage is simply 1Vrms...?

There being 2 possible correct answers, this is only one of them.