To simplify (3x)^2 step by step, recognize that it represents the product of 3x multiplied by itself, which can be expressed as (3x) * (3x). This results in 3^2 * x^2, leading to 9x^2. The general rule for distributing exponents states that (AB)^2 = A^2B^2. Understanding this concept allows for easier manipulation of expressions involving squared terms. The discussion highlights the simplicity of the process and the importance of recalling basic algebraic principles.
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Observeraren
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for example 3x^2 + (3x)^2 is 12x^2
But i don't remember how to brake down (3x)^2 step by step
Greg tells me the feature to generate a new insight announcement is broken, so I am doing this:
https://www.physicsforums.com/insights/fixing-things-which-can-go-wrong-with-complex-numbers/
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes.
I have seen that this is an important subject in maths
My question is what physical applications does such a model apply to?
I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles.
In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra
Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/
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