How Do L and U Sums Differ in Double Summation?

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Homework Statement


Consider any sequence a1, a2,..., an and the nxn array of values bij = aiaj. Which terms in the array are involved in the sums L = Ʃ(between i=1 and n)Ʃ(between j=1 and i) bij
and U = Ʃ(between j=1 and n)Ʃ(between i=1 and j) bij?

Also, by symmetry, show that L=U.

Homework Equations



n/a

The Attempt at a Solution



I've just started this topic and the double summation is really confusing me. Any guidance or suggestions on how to approach this would be really useful thanks.
 
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dbatten said:

Homework Statement


Consider any sequence a1, a2,..., an and the nxn array of values bij = aiaj. Which terms in the array are involved in the sums L = Ʃ(between i=1 and n)Ʃ(between j=1 and i) bij
and U = Ʃ(between j=1 and n)Ʃ(between i=1 and j) bij?

Also, by symmetry, show that L=U.

Homework Equations



The Attempt at a Solution



I've just started this topic and the double summation is really confusing me. Any guidance or suggestions on how to approach this would be really useful thanks.

Just do a small example by hand. Use maybe a 5 by 5 array of bi,j .

a1a1 a1a2 a1a3 a1a4 a1a5

a2a1 a2a2 a2a3 a2a4 a2a5

a3a1 a3a2 a3a3 a3a4 a3a5

a4a1 a4a2 a4a3 a4a4 a4a5

a5a1 a5a2 a5a3 a5a4 a5a5


 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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