How Do Permutations Differ from Combinations in Mathematics?

kasse
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What's the difference between these two:

1) The number of permutations of n distinct objects taken r at a time is \frac{n!}{(n-r)!}

and

2) The number of combinations of n distinct objects taken r at a time is \frac{n!}{r!(n-r)!}

?
 
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Both ideas deal with counting the number of ways to make selections. For the formulas you have,

Permutations
* You have a collection of n distinct items
* You select r of them without replacement
* You are concerned with the order of selection

Combinations
* You have a collection of n distinct items
* You select r of them without replacement
* You are not concerned with the order of selection

Suppose your set is \{a, b, c, d\}<br /> <br /> The number of permutations of 2 things taken from this group is 12. They are (order is first selected, second selected)<br /> a, b<br /> a, c<br /> a, d<br /> b, a<br /> b, c<br /> b, d<br /> c, a<br /> c, b<br /> c, d<br /> d, a<br /> d, b<br /> d, c<br /> <br /> The number of combinations of two things taken from this group is 6. They are<br /> a,b<br /> a,c<br /> a,d<br /> b,c<br /> b,d<br /> c,d<br /> <br /> Think this way: combinations count subsets - order is not important.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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