How Do Point Charges Affect Electric Field Vectors at a Specific Location?

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Homework Help Overview

The problem involves calculating the electric fields at a specific point due to two point charges, one negative and one positive, positioned on the x-axis. The context is within the subject area of electrostatics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the electric fields E1 and E2 at point P using the formula for electric field due to point charges. Some participants question the placement of charge q2 on the x-axis, seeking clarification on its position.

Discussion Status

The discussion is ongoing, with participants exploring the implications of the charge positions and questioning the calculations presented by the original poster. There is no explicit consensus yet, as participants are still clarifying details and assumptions.

Contextual Notes

There is a potential ambiguity regarding the location of charge q2, which may affect the calculations. The original poster's results are questioned, indicating that there may be misunderstandings in the application of the formulas or the interpretation of the charge positions.

sami23
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Homework Statement


Point charge q1= -5.00 is at the origin and point charge q2= +3.00 is on the -x axis at x= 3.00 cm. Point P is on the y-axis at y= 4.00 cm .

Calculate the electric fields E1 and E2 at point P due to the charges q1 and q2. Express your results in terms of unit vectors.


Homework Equations



r = sqrt(x2 + y2)
hat{r} = (vec{r} /r = x hat{i} + y hat{j}) / r
vec{E} = (k * q)/r2 hat{r}


The Attempt at a Solution


E1 will be the vector from q1 to point P
r = sqrt(02 + .042) = .04 m

hat{r} = (0 hat{i} + .04 hat{j})/.04 = 0 hat{i} + 1 hat{j}

E1 = (9*109) * (-5.00*10-9) / .042 (0 hat{i} + 1 hat{j})
= 0 hat{i} - 2.81*104 hat{j}

i did the exact same steps to find E2 and
E2 = 6.47*102 hat{i} + 8.62*102 hat{j}

Am I doing something wrong? According to the steps I used because my answers are wrong and i even followed the way the steps were in the book.
 
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Is q2 at x = +3 cm or at x = -3 cm?
 
q2 is at x=+3 cm = 0.03m
 
sami23 said:
q2 is at x=+3 cm = 0.03m
So how did you end up with a positive i-component?
 

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