How Do Trig Identities Help Calculate Derivatives?

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Homework Help Overview

The discussion revolves around calculating the limit of the expression [Cos(x+h)-Cos(x)]/h as h approaches 0, utilizing trigonometric identities, specifically the cosine addition formula. The context is centered on understanding derivatives through the definition rather than shortcuts typically taught in high school.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the cosine addition formula to the limit problem and mention relevant limits of trigonometric functions that may aid in the calculation.

Discussion Status

Some participants have provided insights into necessary trigonometric limits and suggested starting points for the problem. There is an acknowledgment of the original poster's struggle with the foundational concepts, indicating a supportive environment for exploration.

Contextual Notes

The original poster expresses a lack of preparation from previous instruction, highlighting a potential gap in understanding the formal definition of derivatives. This context may influence the level of guidance needed in the discussion.

Zeihl
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1. Find the limit of [Cos(x+h)-Cos(x)]/h as h approaches 0



2. Solve using trig identity cos(A+B)= cos(A)cos(B)-sin(A)sin(B)



3. My first class using the actual definition of a derivative. My high school teacher just showed us the shorthand and said "good luck when you get to college"... he was only worried about his AP test scores. Any help appreciated
 
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Well you should know how to start this since there is really only one thing you could apply the cos addition formula to.
 
I will mention that somewhere in the middle of working out this problem you will need to know the following facts (that you should have already encountered when discussing limits of trigonometric functions):

[tex]\lim_{h \rightarrow 0} \frac{\sin h}{h} = 1[/tex]

[tex]\lim_{h \rightarrow 0} \frac{\cos h - 1}{h} = 0[/tex]

--Elucidus
 
Weird, I had edited it earlier with my work, but I suppose the internet messed up when trying to submit.

Anyways, I believe I have it correct, thanks anyways.
 

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