How Do Voltage Changes Affect Fields in a Quasi-Electrostatic Capacitor?

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The discussion focuses on calculating the electric and magnetic fields between two parallel circular plates in a quasi-electrostatic capacitor setup, where one plate is grounded and the other has a linearly increasing voltage. The electric field (E field) can be derived from the known parameters, including the permittivity (ε₀) and the radius of the plates (R). The magnetic field (B field) can subsequently be determined using Maxwell's equations, specifically through the relationship involving the time derivative of the electric field. The participants note that the electric field between the plates is uniform when ignoring edge effects. The conversation emphasizes the importance of defining the plate separation for accurate calculations.
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Homework Statement


I am trying to find the electric and magnetic fields between two parallel circular plates, where one plate is grounded and the the other has a voltage that increases linearly with time. I need the E field between plates, and I can ignore fringing fields. The permativity is specified to be ##\epsilon_0##.

Homework Equations


## V(t)=at ## where ##a## is a constant.
The radius of the plates is given to be ##R##

The Attempt at a Solution


##E(\vec{r},t)=\frac{1}{4\pi\epsilon_0}\int\frac{(\vec{r}-\vec{r}')\rho(\vec{r}',t)d^3r'}{|\vec{r}-\vec{r}'|^3}##

##\rho(\vec{r},t)=##?

With the E field I would find the B field using

## \nabla \times B=\mu_0\vec{J}+\frac{1}{c^2}\frac{\partial E}{\partial t} ##
 
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It sounds like a simple parallel plate capacitor setup. You can find the plate area easily enough from the given radius. Do you have a value for plate separation?
 
I would assume that I could just call the plate separation ##d##
 
NotHeisenburg said:
I would assume that I could just call the plate separation ##d##
Sure. And it's well known that, ignoring edge effects, the electric field between the plates of a parallel capacitor is uniform.
 
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