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If we have a particle of mass m moving in the presence of the following potential in one dimension:
V(x) = V0 [(e-2\gammax) - 2e-\gammax)]
In order to find the minimum of the potential V do we take the derivative with respect to x?
dV(x)/dx = 2*\gammaV0[(e-\gammax) - (e-2\gammax)]
Is this how we find the minimum potential of V?
And how do we sketch a graph of V?
V(x) = V0 [(e-2\gammax) - 2e-\gammax)]
In order to find the minimum of the potential V do we take the derivative with respect to x?
dV(x)/dx = 2*\gammaV0[(e-\gammax) - (e-2\gammax)]
Is this how we find the minimum potential of V?
And how do we sketch a graph of V?