How Do You Algebraically Move a Numerator to the Other Side of an Equation?

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To move the numerator in the equation 0.5/Hi = 2.0/8.0 to the other side, the correct approach is to eliminate the fractions by multiplying both sides by the denominators. This results in (0.5)(8.0) = 2.0Hi, simplifying to 4.0 = 2.0Hi. The key algebraic property used here is that multiplying both sides of an equation by the same non-zero value maintains equality. To isolate Hi, further manipulation involves dividing both sides by 2.0, yielding Hi = 4.0/2.0. Understanding these basic rules of fractions is essential for solving such equations effectively.
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I have a formula

Ho / Hi = -So / Si

The question is if I have this:

0.5/Hi = 2.0/8.0

how do I move the 0.5 numerator to the other side of the equation? What is the algebraic property that describes this? I realize this is a simple question but isn't it always the simple ones that get you?
 
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Multiply both numerators by 2. This gives you

1.0/Hi = 4.0/8.0

That should do it.
 
I don't see how that solves the problem.. I need remove the fraction on the left side and keep only Hi. Maybe I am approaching this wrong, if so could someone explain why? I know that 1/Hi is the same as H^-1.
 
I think this belongs in homework help. I will post it there.
 
Quantum Joe said:
I have a formula

Ho / Hi = -So / Si

The question is if I have this:

0.5/Hi = 2.0/8.0

how do I move the 0.5 numerator to the other side of the equation? What is the algebraic property that describes this? I realize this is a simple question but isn't it always the simple ones that get you?

Quantum Joe said:
I don't see how that solves the problem.. I need remove the fraction on the left side and keep only Hi. Maybe I am approaching this wrong, if so could someone explain why? I know that 1/Hi is the same as H^-1.
Then you should have said that to begin with and not just "move the 0.5 numerator to the other side of the equation". In fact, it isn't the numerator that is the problem. To get rid of the fractions multiply both sides of the equations by the denominators:
\frac{0.5}{H_i}(8.0H_i)= \frac{2.0}{8.0}(8.0H_i)
On the left the "Hi" terms cancel and on the right the "8.0" terms cancel:
(0.5)(8.0)= 2.0Hi or 4.0= 2.0Hi.
 
Use these basic rules of fractions:

Given any numbers (denominator \neq 0) ~ \frac{a}{b} * \frac{x}{y} = \frac{ax}{by}

If there are common factors in both the numerator and denominator, you can cancel them out ~
\frac{a}{b} * \frac{x}{a} = \frac{ax}{ba} = \frac{x}{b}

So, \frac{H_o}{H_1}=\frac{-S_o}{S_1}

If you try to make H1 the subject of the equation, it needs to come out of the denominator.
So, to cancel it from the denominator, multiply both sides by H1

\frac{H_o}{H_1}*\frac{H_1}{1}=\frac{-S_o}{S_1}*\frac{H_1}{1}

Simplifying:

\frac{H_o}{1}=\frac{-S_o * H_1}{S_1}

Now that H1 is in the numerator, simply divide/multiply both sides of the equation by the required variable so as to cancel out those variables on the same side as H1:
Multiplying by S1 and dividing by -So

\frac{H_o}{1}*\frac{S_1}{-S_o}=\frac{-S_o * H_1}{S_1}*\frac{S_1}{-S_o}

Simplifying by cancelling common factors in numerator and denominator:

\frac{H_o*S_1}{-S_o}=H_1
 
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