How Do You Approach Tricky Integration Problems Using Trig Identities?

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SUMMARY

The discussion focuses on solving tricky integration problems using trigonometric identities, specifically for the integrals of (cos(x))^4 dx and sec(v) dv. Participants emphasize the importance of utilizing basic trigonometric identities such as sin(2x) = 2sin(x)cos(x) and cos(2x) = 2(cos(x))^2 - 1 to simplify integrals. The integration techniques mentioned include u-substitution and integration by parts, which are essential for tackling complex integrals effectively.

PREREQUISITES
  • Understanding of basic trigonometric identities
  • Familiarity with integration techniques, specifically u-substitution and integration by parts
  • Knowledge of integral calculus
  • Ability to manipulate algebraic expressions involving trigonometric functions
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  • Practice solving integrals using trigonometric identities
  • Learn advanced integration techniques, including integration by parts
  • Explore the application of trigonometric identities in calculus
  • Study the derivation and proof of key trigonometric identities
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Students studying calculus, mathematics educators, and anyone looking to enhance their skills in solving integrals involving trigonometric functions.

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Hello, I'm new to the forums. I've lurked for awhile but I've decided to join up. Anyways, my math professor assigned homework over the break on material he didn't cover in class and is not in our textbook. Any help would be appreciated...

Ok, we're supposed to use basic trig identities to get the integral down to something manageable where we can use u-substitution and/or integration by parts. I've worked out one but I'm having trouble on the other two...

1. the integral of (cos(x))^4 dx. [Hint: also (cos(x)^2)^2]

2. the integral of sec(v) dv. [Hint: multiply sec(v) by (sec(v)+tan(v))/(sec(v)+tan(v)).]

Some identities to use:

sin(2x)=2sin(x)cos(x)

cos(2x)=(cos(x))^2-(sin(x))^2

cos(2x)=2(cos(x))^2-1

cos(2x)=1-2(sin(x))^2

(sin(x))^2=(1/2)[1-COS(2X)]

I'm not looking for the answer, just a push in the right direction, thanks...
 
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Some other useful trigonometric identities:

[tex]\sin^2\frac{x}{2}=\frac{1-\cos x}{2}[/tex],
[tex]\cos^2\frac{x}{2}=\frac{1+\cos x}{2}[/tex].

Edit: actually, these are pretty much the same as your last identity. o:)
 
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