How Do You Calculate Acceleration and Tension in a Two-Body Pulley System?

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SUMMARY

The discussion focuses on calculating acceleration and tension in a two-body pulley system involving a 0.25kg object on a rough surface and a 0.1kg suspended object. The coefficient of kinetic friction is 0.183. The calculated acceleration is 1.5 m/s², derived from the net force equation F_net = mg - friction. The tension in the string is determined using T = Ma + Mgu, where M is the mass of the suspended object and a is the acceleration.

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Homework Statement


Consider the two body system above. There is a 0.25kg object accelerating across a rough surface. The sliding object is attached by a string to a 0.1kg object which is suspended over a pulley. the coefficient of kinetic friction is 0.183. Calculate the acceleration of the block and the tension in the string.

Homework Equations


Fg=mg
Fnet=ma


The Attempt at a Solution



i got the acceleration to be 1.5...m/s^2 i don't know if it is right

fn=fg=mg 0.25 x9.81m/s^2 =2.4525N
ff=ufn
ff=0.183 x 2.4525N =0.4488075 ff=fg since fn=fg

fg2= 0.1 x 9.81 =0.981 then subtracted them to get fnet then divided
 
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Let the driving force (weight of the hanging block-friction of the block on the surface)=the combined mass time acceleration. To solve for a.

mg-Mgu=(m+M)a.

The tension in the string should be the force required to drive the block on the surface against friction at a.

T=Ma+Mgu.



*or so I think, it's been a while since I have done such problems.
 

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