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Diagram
Consider the two body system above. There is a 0.25kg object accelerating across a rough surface. The sliding object is attached by a string to a 0.1kg object which is suspended over a pulley. the coefficient of kinetic friction is 0.183. Calculate the acceleration of the block and the tension in the string.
Fg=mg
Fnet=ma
i got the acceleration to be 1.5...m/s^2 i don't know if it is right
fn=fg=mg 0.25 x9.81m/s^2 =2.4525N
ff=ufn
ff=0.183 x 2.4525N =0.4488075 ff=fg since fn=fg
fg2= 0.1 x 9.81 =0.981 then subtracted them to get fnet then divided by the total mass to get 1.502025m/s^2
=0.4488075N
Homework Statement
Consider the two body system above. There is a 0.25kg object accelerating across a rough surface. The sliding object is attached by a string to a 0.1kg object which is suspended over a pulley. the coefficient of kinetic friction is 0.183. Calculate the acceleration of the block and the tension in the string.
Homework Equations
Fg=mg
Fnet=ma
The Attempt at a Solution
i got the acceleration to be 1.5...m/s^2 i don't know if it is right
fn=fg=mg 0.25 x9.81m/s^2 =2.4525N
ff=ufn
ff=0.183 x 2.4525N =0.4488075 ff=fg since fn=fg
fg2= 0.1 x 9.81 =0.981 then subtracted them to get fnet then divided by the total mass to get 1.502025m/s^2
=0.4488075N
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