How Do You Calculate EMF with Ohm's Law?

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SUMMARY

The discussion focuses on calculating the electromotive force (EMF) of a battery using Ohm's Law. Given a battery with a 0.15-ohm internal resistance and a current of 1.5 A flowing through a 5.0-ohm resistor, the calculation yields an EMF of 7.725 V. The formula applied is V = I (R + r), where R is the external resistance and r is the internal resistance. The calculations presented are confirmed to be correct by participants in the discussion.

PREREQUISITES
  • Understanding of Ohm's Law
  • Basic knowledge of electrical resistance
  • Familiarity with circuit components (batteries and resistors)
  • Ability to perform basic arithmetic operations
NEXT STEPS
  • Study the implications of internal resistance in battery performance
  • Learn about series and parallel resistor configurations
  • Explore advanced applications of Ohm's Law in circuit analysis
  • Investigate the effects of temperature on resistance and EMF
USEFUL FOR

Students in electrical engineering, hobbyists working with circuits, and professionals involved in battery technology and circuit design will benefit from this discussion.

predentalgirl1
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1.What is the emf of a battery with a 0.15-ohm internal resistance if the battery delivers 1.5 A to an externally connected 5.0-ohm resistor?








Given that r = 0.15 ohm , I = 1.5 ohm , R = 5 ohm.

By Ohm’s law V = I ( R + r)
= 1.5 (5.15)
E=7.725 V


Is my work/answer correct?
 
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Looks good to me.
 

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