How Do You Calculate Force on a Passenger in an Accelerating Elevator?

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To calculate the force exerted on a passenger in an accelerating elevator, one must consider both the gravitational force and the force due to acceleration. The passenger's mass is 100 kg, and the elevator accelerates upward at 30 cm/s², which converts to 3 m/s². The net force can be calculated using the formula Fa = ma + mg, where Fa is the total force, m is mass, and g is the acceleration due to gravity (-9.8 m/s²). After correcting for unit conversion, the correct force exerted on the passenger is found to be 680 N. The discussion highlights the importance of understanding force summation and unit conversions in physics calculations.
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I need a little help with this problem. I know what the answer is, but not how to get it.

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A passenger in an elevator has a mass of 100 kg. Calculate the force in Newtons exerted on the passenger by the elevator if the elevator is moving upward with an acceleration of 30 cm/s^2.
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Can anyone help me please?
 
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I would first recommend drawing an FBD. If the elevator is accelerating at 30cm/s2, what is the acceleration of the person?
 
The person should have an acceleration of 30 too, since he's inside the elevator. This gives me:

Sum of Forces = mass x acceleration
Sum of Forces = 100 (30)
Sum of Forces = 3000

When you subtract the force from gravity (-980) the normal force acting on the guy from the elevator is 3980 N, which is much too high. (the correct answer is 1010 N)

I could be misunderstanding this, I'm not great at physics.
 
Okay, your on the right lines but not quite there, did you draw a FBD? Let's first look at the forces involved, let the acceleration force be Fa and let vertically upwards be defined as positive; we therefore have;

\sum\vec{F} = F_{a} - mg

Does that make sense?
 
No, I'm sorry, it doesn't. The only formula I've learned so far is "force equals mass times acceleration" Can you show me how you got the other formula?
 
amenos42 said:
No, I'm sorry, it doesn't. The only formula I've learned so far is "force equals mass times acceleration" Can you show me how you got the other formula?
There is no formula required for this, the above step was just summing the forces or finding the net force.
 
Okay, so mg = 100(-9.8) = -980. I'm not sure about the force of acceleration. Is is 30?
 
amenos42 said:
Okay, so mg = 100(-9.8) = -980. I'm not sure about the force of acceleration. Is is 30?
30 cm/s2, you must first convert this to m/s2. So putting our forumale together;

\sum\vec{F} = m\vec{a}

F_{a} - mg = ma

Do you follow?
 
so:
Fa - mg = ma
Fa = ma + mg
Fa = (100)(3) + (100)(-9.8)
Fa = 680

That doesn't seem right.
 
  • #10
Ah. I got it. The problem was the cm - m conversion. Thanks for the help though. My teacher's a psychopath.
 
  • #11
amenos42 said:
Ah. I got it. The problem was the cm - m conversion. Thanks for the help though. My teacher's a psychopath.
No problem. Why do you say your teacher's a psychopath?
 
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