How Do You Calculate K for a Closed Loop Damping Ratio in Higher Order Systems?

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To calculate the value of K for a closed loop damping ratio of 1/sqrt2 in a higher-order system, one must analyze the complementary sensitivity function T(S) given as (2KS + 4K)/(s^3 + 162S^2 + (320 + 2K)S + 4K). The challenge arises from the presence of a cubic term in the denominator, complicating the fitting of the general equation. The damping ratio, typically defined for second-order systems, raises questions about its applicability to third-order systems. While it is possible to manipulate the poles for critical damping, this does not meet the specified damping ratio requirement. Overall, the discussion highlights the complexities of applying damping ratios in higher-order control systems.
vvl92
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From control systems:
I am asked to find the value of K that gives the closed loop damping ratio of 1/sqrt2.
The value for the complimentary sensitivity is
T(S)=(2KS +4K)/(s^3 +162S^2 +(320+2K)S +4K)
so how do I find the value for K?

I tried putting it in the general equation, but it won't fit since on the bottom, there is a s^3 term, and on the top, there is a s term.

If it is not allowed on physics forums to give a proper answer, then please can you just lead me in the right direction? My notes have nothing in and I can't find anything online!

Thanks!
 
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I don't even know if a damping ratio is defined for a third-order system. I would ask what the definition of damping ratio is for such a system.

To quote Wikipedia: "The damping ratio is a parameter, usually denoted by ζ (zeta),[1] that characterizes the frequency response of a second order ordinary differential equation."

You could force the three poles to all be barely real but that would give you critical damping, not what is asked for. And factoring a 3rd order polynomial is a bear anyway ...

BTW I looked up "complementary sensitivity function" and it's just output/input of a noiseless system. So no help there.
 
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