How Do You Calculate Permutations with Specific Color Constraints?

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To calculate the permutations of aligning 5 balls with specific color constraints from a set of 30 uniquely colored balls, the process involves selecting positions for the blue, red, and yellow balls first. The blue ball can occupy any of the 5 positions, followed by the red ball in 4 remaining positions, and the yellow ball in 3 slots. For the last two positions, there are 27 other balls to choose from, which can be arranged in 27 permute 2 ways. The final calculation is indeed 5*4*3*(27 permute 2). This confirms that the approach to solving the problem is correct.
erogard
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Hi, here's the question, I just need someone to confirm that I'm doing it right (been a while since my last stat class):

Let's say I have 30 balls all of different colors. I want to know in how many different ways I can align 5 balls picked at random (thus ordering matters). Note that one must be blue, one red and one yellow.

So let's start with the blue one. I have 5 different ways to arrange it (either place it first in line, or second, or third etc.). Then let's say I'm looking a the red one: I have 4 ways left to arrange it. Finally I have 3 slots left for the yellow one. Now for the remaining 2 balls, I still have 27 balls to choose from.

Would the answer be 5*4*3*(27 Permute 2)?

Thanks.
 
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erogard said:
Hi, here's the question, I just need someone to confirm that I'm doing it right (been a while since my last stat class):

Let's say I have 30 balls all of different colors. I want to know in how many different ways I can align 5 balls picked at random (thus ordering matters). Note that one must be blue, one red and one yellow.

So let's start with the blue one. I have 5 different ways to arrange it (either place it first in line, or second, or third etc.). Then let's say I'm looking a the red one: I have 4 ways left to arrange it. Finally I have 3 slots left for the yellow one. Now for the remaining 2 balls, I still have 27 balls to choose from.

Would the answer be 5*4*3*(27 Permute 2)?

Thanks.

Yes.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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