How Do You Calculate the Angle of a Slipping Ladder?

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New user has been reminded that showing an attempt at the solution is mandatory in homework threads at the PF.

Homework Statement


A 75 kg man stands on a 8meter 25kg ladder at 6 meters above the bottom when it just starts to slip. Mu(s) is.3. What is the angle of the ladder?

ladder mass=25kg
ladder length=8m
man mass= 75kg
radius of man slipping = 6m
Mu=.3
angle= ?

Homework Equations


F= Mu x Normal force
Torque=rFsintheta
X: P=F(s)=Mu(s) x Normal Force = Mu(s) (Weight of ladder + Weight of man) = Mu(s) (Ladder mass x g + mass man x g)
Y: Normal force = weight of ladder + weight of man
(radius of p)(P)(sin angle)= (radius of ladder)(weight of ladder)(cos theta)+(height of man slipping)(weight of man)(cos theta)

The Attempt at a Solution


not sure where to start... [/B]
 
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physicsstudent101 said:
not sure where to start...
As with ALL such problems, you start with a force vector diagram. That generally clarifies how all the forces interact and gives you a starting point for writing equations.
 
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