How Do You Calculate the Center of Mass of a Composite Slab?

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SUMMARY

The calculation of the center of mass for a composite slab consisting of aluminum and iron involves determining the individual masses and their respective coordinates. Given dimensions of d1=11.0cm, d2=2.80cm, and d3=13.0cm, the mass of aluminum is calculated as 1081.08g and the mass of iron as 3143.17g. The center of mass can be found along the thickness direction (5.6cm) by using the mass and center of mass positions of each material. The symmetry of the slab simplifies the calculation, as the center of mass lies along the central axis of the rectangular faces.

PREREQUISITES
  • Understanding of composite materials and their properties
  • Knowledge of density calculations and mass determination
  • Familiarity with the concept of center of mass
  • Basic geometry involving rectangular solids
NEXT STEPS
  • Study the principles of calculating the center of mass for composite objects
  • Learn about density and volume calculations in materials science
  • Explore symmetry in physical systems and its implications for center of mass
  • Investigate the effects of varying material densities on composite structures
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Students in physics or engineering, materials scientists, and anyone involved in structural analysis of composite materials.

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1. A composite slab has dimensions of d1=11.0cm, d2=2.80cm, and d3=13.0cm. Half the slab consists of aluminum (density=2.70g/cm^3) and half consists of iron (density=7.85g/cm^3). What are the x coordinate, y coordinate, and z coordinate of the slab's center of mass?

There's a figure in my book where the dimensions are for each the iron and aluminum. In other words, if you find the volume using the dimensions they give you, if you double it you have the volume for the whole figure.


I have no idea where to even begin.
I found the volume for each piece to be 400.4g

I tried finding the mass for each using p=m/v.
For the aluminum I got m=(400.4cm^3)(2.70g/cm^3) = 1081.08g
For the iron I got m=(400.4cm^3)(7.85g/cm^3) = 3143.17g


No clue how to find x, y, and z...help please!
 
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If you are saying that each metal is a rectangle 11cm x 13cm with a thickness of 2.8cm stacked to make a total thickness of 5.6cm, then by symmetry the CM position is on a line through the centers of the big ractangular faces. You just need to find the position along the direction of the 5.6cm thickness. You can do that by using the mass and the CM positions of the individual metals.
 

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