How Do You Calculate the Final Velocity of a Projectile?

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SUMMARY

The final velocity of a projectile can be calculated using the equations of motion under gravity. In this discussion, a rock is thrown from a 50m cliff with an initial velocity of 7m/s at an angle of 53 degrees. The relevant equations include vfy = sin(theta) * vi - gt and vf^2 = (vi * sin(theta))^2 - 2gy. The correct approach involves determining the time of flight and correctly applying the equations to find the final velocity, which should yield a result of 32 m/s.

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Homework Statement


A rock is thrown from a cliff that is 50m long with an initial velocity of 7m/s and an angle of 53, find the rock's veloctity before it hits the ground

Homework Equations


vfy=sin(theta)*vi-gt
vf^2=(vi*sin(theta))^2-2gy

The Attempt at a Solution


x=vi*cos()t
t=x/(vi*cos)
x=7*cos(53)-2*9.81*(x/(vi*cos(53)))^2
x =2.49 or x=-6.11
at this point i tried to plug in x into vf^2=(vicos)^2-2gy
but none of them give 32 m/s which is the answer according to the answer's sheet
 
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Some questions for you to consider:
In your solution what is x? It appears you are using x to represent two different quantities.
Why do you think the time of flight is given by your second equation?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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