How Do You Calculate the Holding Force of a Water Nozzle?

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SUMMARY

The discussion focuses on calculating the holding force of a water nozzle with a radius of 25mm and a flow rate of 750L/min. The key equations involved include F = m × a, Δm / Δt = pAv, and R = vA. The calculated fluid velocity is 6.366 m/s, and the pressure required to achieve the holding force of 79N is approximately 40,000 pascals. The solution emphasizes the importance of understanding fluid dynamics and pressure calculations in this context.

PREREQUISITES
  • Fluid dynamics principles
  • Basic knowledge of pressure calculations
  • Understanding of the continuity equation (A_1 × v_1 = A_2 × v_2)
  • Familiarity with Newton's second law (F = m × a)
NEXT STEPS
  • Study the impulse-momentum equation in fluid mechanics
  • Learn about pressure measurement techniques in fluid systems
  • Explore advanced fluid dynamics simulations using software like ANSYS Fluent
  • Investigate the relationship between flow rate and nozzle design
USEFUL FOR

Engineers, physics students, and anyone involved in fluid mechanics or nozzle design will benefit from this discussion.

techninja
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Homework Statement


A nozzle has a radius of 25mm. Water emerges at the rate of 750L/min. Find the force with which the nozzle must be held.

Homework Equations


F = m \times a
\Delta m / \Delta t = pAv
A_1 \times v_1 = A_2 \times v_2
R = vA

The Attempt at a Solution


I've so far been able to calculate fluid velocity: v = r/A = 6.366m/s. However, finding pressure in order to find force eludes me. I've tried looking into different units, trying the above formulae (but there's always one variable somehow dangling somewhere), and so on.

The answer is given to be 79N, so I do know that pressure is equal to about 40000 pascals. This, of course, doesn't help much.

Any help is very much appreciated. :redface:
 
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Try looking at a variation of the impulse-momentum equation, Ft = m delta v
 
Thank you verily much for your input. I completely understand now. (:
 

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