How do you calculate the impedance of the primary circuit?

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To calculate the impedance of the primary circuit, the mutual inductance (M) has been determined as 106.3μH using the formula M=U2/(ω*I1). The focus is on deriving the formula needed to calculate Z1 rather than obtaining specific numerical values. Clarification is sought regarding the connection of the secondary circuit, which may influence the impedance calculations. Understanding the relationship between the primary and secondary circuits is essential for accurate impedance determination. The discussion emphasizes the need for a formulaic approach to calculate Z1 based on the given parameters.
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Homework Statement
I have an assignment that I need to do regarding magnetically coupled coils, but I'm stuck at a point. If we know the following: f=5000Hz, the distance between coils, x=20mm, the voltages U1=3.18V U2=336mV, the current I1=100.6mA, N1=250, N2=1000, how can I calculate the impedance of the primary circuit, Z1? I've looked it up online but I can't find any formulas with these particular given data. Any ideas?
Relevant Equations
M = U2/(ω*I1)
I'm not sure if it helps for what I'm looking, but I've calculated the mutual inductance, M, using the equation: M=U2/(ω*I1) = 106.3μH. I don't need the numerical value in particular, I just want to find a way to deduce the formula in order to calculate Z1. Thank you!
 
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Do we know what the secondary is connected to?
 
Thread 'Chain falling out of a horizontal tube onto a table'

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
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