How Do You Calculate the Launch Angle and Velocity of a Cannonball?

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To calculate the launch angle and velocity of a cannonball, one must consider the projectile motion equations, specifically those for distance and height. Given the total distance of 79.5 meters and the wall's position at 67.5 meters with a height of 17.58 meters, two key equations can be derived. The gravitational constant of 9.81 meters per second squared is essential for these calculations. By analyzing the projectile's maximum height and range, the allowable launch angle and initial velocity can be determined. Understanding these principles is crucial for solving the problem accurately.
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Ok, I am having a hard time understanding how to approach this problem the correct way interms of physics.

A cannon shoots a ball going a total distance of 79.5 meters, clearing a wall 67.5 meters away from where it was initially shot. The wall is 17.58 meters high, what is the allowable launch angle and velocity? Assume gravity is 9.81 meters per second squared.
 
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canon

draw the projectile
list all the equations of a projectile
try to calculate the maximum heigt
try to find range
 
Write down the formulas for distance and height of a projectile depending on angle and initial speed. You know that the range (distance until the height is 0 again) is 79.5 and that the height 67.5 meters away is at least 17.58 meters. That gives you two equations for angle and speed.
 
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