How Do You Calculate the Probability of a Heart Attack in a High-Risk Group?

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Discussion Overview

The discussion revolves around calculating the probability of at least one person having suffered a heart attack in a high-risk group, specifically when selecting four individuals. The focus includes mathematical reasoning and the interpretation of probability concepts.

Discussion Character

  • Homework-related, Mathematical reasoning, Debate/contested

Main Points Raised

  • One participant presents an initial calculation suggesting a probability of 2.8, which is questioned by others.
  • Another participant proposes considering the probability that none of the individuals have had a heart attack, suggesting a different approach to the problem.
  • A third participant asserts that the event is not dependent and provides a formula for calculating the probability of at least one heart attack based on the complement of none occurring.
  • A later reply supports the third participant's approach, stating that the initial calculation does not make sense and emphasizes that probabilities cannot exceed 1.

Areas of Agreement / Disagreement

Participants express disagreement regarding the initial calculation and the interpretation of dependence in the events. Multiple competing views on the correct approach to the probability calculation remain unresolved.

Contextual Notes

Participants highlight the importance of understanding the nature of the events (dependent vs. independent) and the implications for probability calculations, but do not resolve these issues.

Who May Find This Useful

Students or individuals interested in probability theory, particularly in the context of health statistics and risk assessment.

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Homework Statement



In a certain high-risk group, the chance of a person having suffered a heart attack is 70%. If four persons are chosen from the group, find the probability that at least one will have had a heart attack.

Homework Equations



(work shown below) these would be dependent

The Attempt at a Solution



(.7)/(4) = 2.8
 
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It might be easier to think of the chance that a specific individual doesn't have a heart attack, so what are the chances that none of the individuals have heart attacks (and you might want to rethink the dependence).
 
your answer is wrong
i don think it is a dependent event

the probability of a person with heart attack is 0.7

so the probability that among 4 at least 1 has heart attack = 1 - probability that none have

= 1 - (0.3)[itex]^{4}[/itex]
must be correct but verify it
 
Amateur's answer is correct.

Your attempt doesn't make any sense.
Remember: probability can never be more than 1.

So if you find 2.8, think again.
 

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