How Do You Calculate the Q Factor of a Harmonic Oscillator?

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SUMMARY

The Q factor of a harmonic oscillator is calculated using the formula Q = (resonant frequency)/(width of resonance). In this discussion, the resonant frequency is given as 390 Hz, and the amplitude is expressed as 20.0 F_0/m. The user initially attempted to calculate Q using incorrect unit conversions, leading to erroneous results. Ultimately, the user recognized that F_0/m represents variables related to maximum driving force and mass, indicating a need to derive the width of resonance from these variables for accurate Q factor calculation.

PREREQUISITES
  • Understanding of harmonic oscillators and their properties
  • Familiarity with the concept of resonant frequency
  • Knowledge of amplitude and its relation to driving force and mass
  • Basic grasp of unit conversions in physics
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Students studying physics, particularly those focusing on oscillatory motion, as well as educators seeking to clarify concepts related to the Q factor in harmonic oscillators.

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Homework Statement


The amplitude of a driven harmonic oscillator reaches a value of 20.0 F_0 /m at a resonant frequency of 390 Hz.
What is the Q value of this system?

Since our Professor accidentally gave us the problem set from a different book instead of the one we have, and the one we have makes no mention of Q, the only introduction I have to Q value is a few sentences near the end of class, and it is just confusing me to no end.

Homework Equations


Okay, so as far as I know, Q value is equal to the resonant frequency (w_0) over the width of the resonance. I have several equations relating q to nu (v) and the resonant frequency:

Q = (resonant frequency)/(width of resonance)

Q = (w_0/ v) where v is nu

and

width of resonance at K = Kmax/sqrt(2) = W

The Attempt at a Solution


The main trouble I am having with this problem is trying to figure out how to use the two units given to convert and insert them into the equations I was given. I have assumed that the resonant frequency of 390 Hz was equal to w_0. After this, I have tried several methods to get the final answer:

At first I attempted to insert 390 into w_0 and 20 F_0/m into v and find Q that way.
This resulted in Q = (w_0/v) = 19.5, which was incorrect, and the units are probably off (since Q is unitless)

After this, I tried to use the equation where width = Kmax/sqrt(2). I substituted 20 F_0/m into Kmax and got a width of 14.142 F_0/m. I then substituted this value into the Q equation where: Q = (390 Hz / 14.142 F_0/m) = 27.577, which is incorrect, and again I am pretty sure that my units are off.

After this, I had only two more chances to answer the question so I have just been searching for how to convert the Amplitude given into a width of resonance with no success. Can anybody help me go through the process of converting the two values given into values that I can use in the Q equation?

Thank you to anyone who replies
 
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Actually I just figured out another part of the problem. I now think that the units [tex]F_0[/tex] / m are actually values themselves represented by variables.

F0 = maximum driving force

and m is the mass of the object.

This just means that now I think I have to find a way to take this amplitude and plug it into something that gives me the range of resonance frequency values to divide the resonant frequency by. Anyone have any idea how I would go about doing that?
 
anybody have any ideas at all?
 

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