How Do You Calculate the Speed of a Proton and Alpha Particle from a Decaying Lithium Isotope?

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To calculate the speeds of the proton and alpha particle from the decay of the unstable lithium isotope 5^Li, conservation of momentum is crucial. The total momentum before the decay is zero, as the nucleus is at rest, so the momentum of the proton and alpha particle must be equal and opposite after the decay. The total kinetic energy released during the decay is 2.70E-13 J, which can be used alongside the masses of the proton and alpha particle to determine their speeds. By applying these principles, the velocities of both particles can be calculated. Understanding these concepts is essential for solving the problem effectively.
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I seem to be stuck on this problem. I thought calculating the velocity of the center of mass of the system would get me somewhere, but I remain confused about where to go next. Here is the problem:
The light isotope, 5^Li is unstable and breaks up spontaneously into a proton (hydrogen nucleus) and an alpha particle(helium nucleus). In this process, a total energy of 2.70E-13 J is released, appearing as the kinetic energy of the two reaction products. Determine the speeds of the proton and the alpha particle that arise from the decay of a 5^Li nucleus at rest. (Note: the two masses of the proton and alpha particle are m(proton)=1.67E-27 kg and m(alpha particle) = 4m(proton) = 6.68E-27kg).
The answer may be more simpler than I am realizing...or way more difficult. Any assitance on this problem would be GREATLY appreciated. THANKS!
 
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wildrjetta said:
I seem to be stuck on this problem. I thought calculating the velocity of the center of mass of the system would get me somewhere, but I remain confused about where to go next. Here is the problem:
The light isotope, 5^Li is unstable and breaks up spontaneously into a proton (hydrogen nucleus) and an alpha particle(helium nucleus). In this process, a total energy of 2.70E-13 J is released, appearing as the kinetic energy of the two reaction products. Determine the speeds of the proton and the alpha particle that arise from the decay of a 5^Li nucleus at rest. (Note: the two masses of the proton and alpha particle are m(proton)=1.67E-27 kg and m(alpha particle) = 4m(proton) = 6.68E-27kg).
The answer may be more simpler than I am realizing...or way more difficult. Any assitance on this problem would be GREATLY appreciated. THANKS!

I think what you're missing is conservation of momentum. The momentum of the system before the decay must be the same as after the decay. I think this, along with the fact that you are given the amount of energy released will allow you to calculate the speeds of the reaction products.
 
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