How Do You Calculate the Volume of a Cylinder Using Triple Integrals?

  • Thread starter Thread starter Bowenwww
  • Start date Start date
  • Tags Tags
    Cylinder Volume
Click For Summary
SUMMARY

The volume of a cylinder defined by the equation x² + y² = 4R² can be calculated using triple integrals in cylindrical coordinates. The correct limits for the triple integral are: θ from 0 to 2π, r from 0 to 2R, and z from 0 to (3r² + 2r²)/R. The confusion arose from incorrect assumptions about the radius and limits, which should be clarified to avoid calculation errors.

PREREQUISITES
  • Cylindrical coordinates in calculus
  • Understanding of triple integrals
  • Basic knowledge of volume calculations
  • Familiarity with the equation of a cylinder
NEXT STEPS
  • Study the derivation of triple integrals in cylindrical coordinates
  • Practice calculating volumes of solids using triple integrals
  • Explore the application of triple integrals in physics and engineering
  • Learn about the differences between Cartesian and cylindrical coordinate systems
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with volume calculations and integrals, particularly those focusing on cylindrical shapes.

Bowenwww
Messages
25
Reaction score
0
Cylinder volume problem Please Help!

Basically I've been attempting this question for at least 3 days now and it's driving me insane. The question goes like this - Consider the volume V inside a cylinder x^2 + y^2 = 4R^2 between z=(3x^2 + 2y^2)/R and the xy plane, xyz are cartesian and R is constant - Write down a triple integral using cylindrical co-ordinates for the volume V giving 3 upper and 3 lower limits




I first started by stating that r = 4R^2 The first limit (LHS to RHS) should surely be 0 to 2π the second should be from the origin to the radius i.e. 0 to 4R^2 and the third limit should be 0 to Z but I'm having a nightmare solving it or finding the right limits, any help would be greatly appreciated as I'm losing serious patience :( TIA.
 
Physics news on Phys.org


What does your triple integral look like?

And by the way, the radius is r is from the origin 0 to R ( not 0 to 4R^2)
 


256bits said:
What does your triple integral look like?

And by the way, the radius is r is from the origin 0 to R ( not 0 to 4R^2)

Gee. No response. Radius of circle is 2R.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
3K
Replies
4
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K