How Do You Continue Expanding and Simplifying the Dot Product (2u+v)⋅(u-2v)?

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To expand and simplify the expression (2u+v)⋅(u-2v), the initial expansion yields 2u⋅u + 2u⋅(-2v) + v⋅u + v⋅(-2v). This can be combined to give 2(u⋅u) - 4(u⋅v) - 2(v⋅v). Further simplification using the magnitudes of the vectors results in the expression |u|² - 3(u⋅v) - 2|v|². The discussion emphasizes careful combination of terms and the use of vector magnitudes for simplification. The final expression effectively summarizes the dot product expansion.
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How do you expand and simplify this one?


(2u+v).(u-2v)
=2u.u+2u.(-2v)+v.u+v.(-2v)

Where u and v are vectors and the "." is the dot. I did some but after this I am lost, how can I continue?
 
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I don't see what your problem is. You have done
(2u+v).(u-2v)=2u.u+2u.(-2v)+v.u+v.(-2v) correctly. Now just
combine 2u.(-2v)= -4 u.v and v.u which is also u.v:
This is 2(u.u)- 3 u.v- 2(v.v)

You can also use the fact that |u|= sqrt(u.u) so that
u.u= |u|2 and v.v= |v|2 so that
(2u+v).(u-2v)= |u|2- 3u.v- 2|v|2.
 
Got it, thanks :smile:
 
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