How Do You Correctly Expand Trigonometric Equations Involving Sine and ArcTan?

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SUMMARY

The discussion focuses on expanding trigonometric equations involving sine and the arctangent function. The correct expansion of the expression (B^2+C^2)^(1/2) * sin(omega*t + taninverse(B/C) is achieved using the sine addition formula: sin(x + y) = sin(x)cos(y) + cos(x)sin(y). The user initially misapplied trigonometric identities, resulting in an incorrect expression of B arctan(omega^2(t)) + C cos(omega*t). The correct result is B cos(omega*t) + C sin(omega*t), which was clarified through the application of sine and cosine of the arctangent function.

PREREQUISITES
  • Understanding of trigonometric identities, specifically the sine addition formula.
  • Familiarity with the arctangent function and its properties.
  • Basic algebraic manipulation skills.
  • Knowledge of the relationship between sine, cosine, and arctangent functions.
NEXT STEPS
  • Study the sine addition formula in detail to understand its applications.
  • Learn how to derive sine and cosine from the arctangent function.
  • Practice expanding trigonometric expressions using various identities.
  • Explore advanced trigonometric identities and their proofs for deeper comprehension.
USEFUL FOR

Students, educators, and professionals in mathematics or physics who are working with trigonometric equations and need to accurately expand expressions involving sine and arctangent functions.

ultrabionic_ang
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hello.. I've been having some trouble with expanding this:

(B^2+C^2)^(1/2) X sin (omega*t +(taninverse B/C)

(read as: square root of (b squared plus c squared) times sin times the quantity omega times t plus taninverse of B divided by C)

apparently, the answer is supposed to be B cos omega*t + C sin omega*t .. but I've gotten like B arctan omega^2(t) + C cos omega*t... i just wanted to know like the way to get the answer.. i think I'm using trig identities incorrectly..
 
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What you need is [itex]\sin (x + y) = \sin x \cos y + \cos x \sin y[/itex] and use the fact that [itex]\sin \tan^{-1} x = x/ \sqrt {1 + x^2}[/itex] and similarly for the cosine.
 
thanks! that helped a lot! thank you!
 

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