How Do You Derive an Explicit Formula from an Integral Equation?

  • Thread starter Thread starter matrix_204
  • Start date Start date
  • Tags Tags
    Explicit Formula
Click For Summary
SUMMARY

The discussion focuses on deriving an explicit formula from an integral equation, specifically examining the integral of the function tangent, represented as F(x) = ∫0x tg(t) dt = x + x2. The participants emphasize the application of the Fundamental Theorem of Calculus, which states that F'(x) = f(x), and discuss the challenges of finding an antiderivative when it is not readily apparent. The conversation highlights the necessity of understanding various integration techniques and the graphical interpretation of area under the curve to derive functions from their integrals.

PREREQUISITES
  • Fundamental Theorem of Calculus
  • Integration techniques, including integration by parts
  • Understanding of antiderivatives
  • Graphical interpretation of integrals and areas under curves
NEXT STEPS
  • Study integration by parts in detail
  • Explore various methods of finding antiderivatives
  • Learn about graphical interpretations of integrals
  • Investigate specific functions and their properties related to integration
USEFUL FOR

Students of calculus, mathematics educators, and anyone interested in deepening their understanding of integral equations and the Fundamental Theorem of Calculus.

matrix_204
Messages
99
Reaction score
0
How do u find an explicit formula when given an integral of a function.
For example, the integral from 0 to x of tg(t)dt=x+x^2, how do u find the formula for g(t)?
 
Physics news on Phys.org
This involves a portion of the Fundamental Theorem of Calculus which says:

The function:

F(x) = \int_{0}^{x} f(t) dt

is an indefinite integral or antiderivative of f. That is:

F'(x) = f(x)

Explicit form is simply in terms of a function F.
 
Evaluate that integral by parts...(You could have written t*g(t),the way you did,it can be mistaken with "tangent" of 't').

Daniel.
 
There is no general method. We do integration by using the "anti-derivative" of a function f: a function F whose derivative is f- and that often is a matter of "remembering" a correct f. There are ways of altering a function whose anti-derivative you do not immediately "remember" to a simpler function with a related anti-derivative- but those are often "ad hoc" and can be used only for certain situations. One of annoying things about learning (and teaching) "Calculus II" (generally "methods of integration" is that you have to learn many unrelated "methods" (tricks) that work only in limited situations.
 
Last edited by a moderator:
Speaking about the Fundamental thm of calculus, i was wondering why is it that for F(x)= int from 0 to x for f(t)dt, the function F is the constant function 0?
 
Here, matrix_204, is the is the simplest answer you could possibly find:

Consider a function f(x). If this function is smooth, we can naturally associate with it another function A(x), defined as "the area between f(x) and the x-axis counted from the point x = 0 to x". We do not have a formula for A(x), but we know that it is a function because for each value x there is only one area A.

Now, consider breaking up the area under the curve f into many infinitesimally thin rectangles (the same type rectangles we use in a Reimann sum), each of which has an infinitesimal area dA. This is a very graphical argument, so I hope you are picturing these little rectangles dA. Now, how can we express the area of a little rectangle dA in terms of its height and width?

The height of the rectangle at point x is f(x) and the width of the rectangle is dx. So we have established the fundamental theorem:

dA = f(x) dx

dA/dx = f(x)

Now we can find a formula for A(x), it is the function whose derivative is f(x).

I am curious to see what anyone thinks of this derivation (which I made up, but do not expect to be unique to me). Obviously, it is about the loosest thing this side of Newton's fluxions, but in a certain real sense it works.
 
matrix_204 said:
Speaking about the Fundamental thm of calculus, i was wondering why is it that for F(x)= int from 0 to x for f(t)dt, the function F is the constant function 0?



It isn't,unless the integrand is identically zero

f(t) \equiv 0.

Daniel.
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
2K
Replies
11
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
6
Views
2K
  • · Replies 27 ·
Replies
27
Views
1K
Replies
51
Views
4K
Replies
13
Views
2K