How Do You Derive f(x) = 1/(ln(x)^2)?

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SUMMARY

The derivative of the function f(x) = 1/(ln(x)^2) is calculated using the chain rule and the derivative of the natural logarithm. The correct steps yield f'(x) = -2/(x * ln(x)^3). The process involves rewriting the function as (ln(x))^-2, applying the power rule, and then multiplying by the derivative of ln(x), which is 1/x. This method confirms the accuracy of the derivative calculation.

PREREQUISITES
  • Understanding of calculus, specifically differentiation techniques
  • Familiarity with the chain rule and power rule in calculus
  • Knowledge of the natural logarithm function and its properties
  • Ability to manipulate algebraic expressions involving exponents
NEXT STEPS
  • Study the chain rule in calculus for more complex derivatives
  • Practice differentiating functions involving logarithmic expressions
  • Explore applications of derivatives in real-world scenarios
  • Learn about higher-order derivatives and their significance
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Students studying calculus, mathematics educators, and anyone seeking to improve their skills in differentiation and understanding logarithmic functions.

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Homework Statement



Find the derivative of f(x):
f(x)= 1/ ((ln(x)^2))


Homework Equations



f(x)= ln(x)
f'(x)= 1/((ln(x))

The Attempt at a Solution



Dx(1/ln(x)^2) =
Dx((ln(x))^-2)=
-2*(ln(x)^-3) * Dx(ln(x)) =
-2*(ln(x)^-3) * 1/x =
-2/(x*ln(x)^3)

Are these the correct steps? I'm getting myself confused
 
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This is correct.
 

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