How Do You Derive the Compton Effect Equation from Conservation Laws?

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SUMMARY

The discussion focuses on deriving the Compton effect equation (\(\lambda' - \lambda = \frac{h}{m_ec}(1 - \cos\theta)\)) using conservation laws. Participants reference three key equations related to momentum and energy conservation. The equations involve Planck's constant \(h\), Lorentz factor \(\gamma\), and the mass-energy equivalence principle. The solution involves eliminating the angle \(\phi\) using trigonometric identities and squaring the equations to facilitate the derivation.

PREREQUISITES
  • Understanding of the Compton effect and its significance in quantum mechanics.
  • Familiarity with conservation laws in physics, specifically momentum and energy conservation.
  • Knowledge of trigonometric identities, particularly \(\cos^2(\phi) + \sin^2(\phi) = 1\).
  • Basic grasp of relativistic equations, including the Lorentz factor \(\gamma\) and its relationship to velocity \(u\).
NEXT STEPS
  • Study the derivation of the Compton effect equation in detail, focusing on momentum and energy conservation.
  • Learn about the implications of the Lorentz factor \(\gamma\) in relativistic physics.
  • Explore trigonometric identities and their applications in physics problems.
  • Review examples of Compton scattering experiments and their results to understand practical applications.
USEFUL FOR

Physics students, educators, and researchers interested in quantum mechanics, specifically those studying the Compton effect and its derivation from fundamental principles.

gotojason
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oK SO... I have been given the task of deriving the Compton effect equ. ( [tex]\lambda\prime-\lambda=\frac{h}{m_ec}(1-cos\theta)[/tex])
exactly from the 3 following:
1) [tex]\frac{h}{\lambda}=\frac{h}{\lambda\prime}cos\theta +\gamma m u cos\phi[/tex]

2) [tex]0=\frac{h}{\lambda\prime}sin\theta-\gamma mu sin\phi[/tex]

3) [tex]\frac{hc}{\lambda}=\frac{hc}{\lambda\prime}+(\gamma-1)mc^2[/tex]

I found the link
http://en.wikipedia.org/wiki/Compton_scattering
however I am having a hard time going from my equations to momentum and energy conservation
any ideas where to go ... I have been at it for 4+hrs and its driving me nuts
Thanks
 
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To get rid of term of [tex]\phi[/tex], try

[tex]\frac{h}{\lambda}\,-\,\frac{h}{\lambda'}cos\theta\,=\,\gamma m u cos\phi[/tex]


[tex]\frac{h}{\lambda'}sin\theta\,=\,\gamma mu sin\phi[/tex]


Square both equations and add.

Now, IIRC, [itex]\beta[/itex] = u/c and [itex]\gamma[/itex] = [tex]\frac{1}{\sqrt{1-\beta^2}}[/tex]
 
1 and 2 are from momentum conservation and 3 from energy conservation.

First you need to eliminate Phi from the two first equations using the indentity cos^2(phi)+sin^2(phi)=1. Yes, you need to square up these equations after moving all other terms to one side except one with Phi.
 

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