How do you determine conservation of momentum

AI Thread Summary
To determine conservation of momentum, the change in momentum must be within the range of measurement error. In this case, the change in momentum of -8.00 x 10-3 is not zero when considering the error of 1.22 x 10-3. This indicates that the experiment does not prove conservation of momentum, as the measured value does not fall within the acceptable error range. Additionally, it is crucial to account for errors in both initial and final momentum measurements. Understanding these principles is essential for accurately assessing conservation of momentum in experiments.
NewDaddyJones
Messages
6
Reaction score
0
In my lab, I have the change in momentum = -8.00 x 10-3 and my error of change in momentum = 1.22 x 10-3.

Does my change in momentum have to be lower than my error of conservation in order to prove conservation of momentum? Then none of my procedures prove this, even though my average error of time is 3.95 x 10-3.
 
Physics news on Phys.org
-4.00 x 10-3
 
That was wrong because you have to account for the errors of initial momentum and final momentum. I'm just asking how do you prove conservation of momentum, anyway, not any specific values.
 
Could you perhaps elaborate on your experiment, as well as giving us some units to your measurements.
 
Welcome to PF!

Hi NewDaddyJones! Welcome to PF! :smile:

(try using the X2 icon just above the Reply box :wink:)
NewDaddyJones said:
In my lab, I have the change in momentum = -8.00 x 10-3 and my error of change in momentum = 1.22 x 10-3.

Does my change in momentum have to be lower than my error of conservation in order to prove conservation of momentum? Then none of my procedures prove this, even though my average error of time is 3.95 x 10-3.

if your measurement is 8.00 10-3, and your error is 1.22 10-3, then that's 8.00 ± 1.22 10-3, which isn't zero!

Congratulations! :approve:

You have successfully disproved most of classical physics! :wink:
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top