- #1

helpm3pl3ase

- 79

- 0

The derivative is 1-ln(x)\x^2

I need to find the absolute max and absolute min. Now I know I need to find the critical numbers first then plug into f(x) but I am having trouble finding the critical numbers..

x^2 = 0 so x = 0

1-ln(x) = 0 so x = e

But now Iam confused on what to do. Thanks