How Do You Differentiate K sin(Gx + 5)?

  • Thread starter Thread starter imy786
  • Start date Start date
  • Tags Tags
    Differentiating
imy786
Messages
321
Reaction score
0

Homework Statement



if y = K sin(Gx + 5)

what is dy/dx

Homework Equations



y=sin x

dy/dx = cos x

The Attempt at a Solution



y = K sin(Gx + 5)

dy/dx = KG cos (Gx +5) (1)

or

dy/dx = KG cos GX + 5 (2)


i think it is (1)

is this correct or it is non of these (other)?
 
Physics news on Phys.org
Why would you think it is (2) in the first place?
(1) is certainly correct, but your doubt indicates you are not quite familiar with the rules of differentiation yet.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top