How do you find a limit as it aproaches infiniti

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SUMMARY

The limit of sin(x) as x approaches infinity does not exist because the function oscillates between -1 and 1 without settling on a specific value. As x increases, sin(x) continues to vary indefinitely, confirming that there is no convergence to a limit. This conclusion is supported by the behavior of the sine function, which is periodic and bounded.

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Homework Statement


limit x->infiniti sinx=


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The Attempt at a Solution

 
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as x-->infinity values of sinx fall between 1 and -1 meaning that as x approaches infinity, sinx doesn't approach a specific value and so the limit doesn't exist
 
I was sorely tempted to say that the limit as "it" approaches infinity must be infinity!

Of course, you mean the limit as x approaches infinity. As rock.freak667 said, look at what happens to sin(x) as x gets larger and larger- no matter how large x is, sin(x) keeps varying between -1 and 1. It does not "approach" and one number and so there is no limit.
 

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