How Do You Find All Ring Homomorphisms for Specific Mappings?

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Homework Help Overview

The discussion revolves around finding all ring homomorphisms between various rings, specifically from Z to Z, Z2 to Z6, and Z6 to Z2. Participants are exploring the properties and definitions of ring homomorphisms as they relate to these mappings.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to understand the requirements for ring homomorphisms and how to apply the definition to find specific mappings. Questions arise about how to demonstrate the properties of homomorphisms and the implications of the definitions provided.

Discussion Status

Some participants have offered insights into the properties of homomorphisms, suggesting that the definition can guide the determination of mappings. There is an acknowledgment of the challenges faced, with some expressing frustration about the abstract nature of the material. Multiple interpretations of the problem are being explored, but no consensus has been reached.

Contextual Notes

Participants note the constraints of the problem, including the limited elements in Z2 and Z6, and the requirement that the mappings must satisfy specific homomorphic properties. There is also a mention of the unique nature of homomorphisms from Z to other rings based on the identity element.

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Homework Statement


Find all ring homomorphisms \phi: Z \rightarrow Z
\phi: Z2 \rightarrow Z6
\phi: Z6 \rightarrow Z2


Homework Equations


A function \phi: R \rightarrow S is called a ring homomorphism if for all a,b\inR,
\phi(a+b) = \phi(a) + \phi(b)
\phi(ab) = \phi(a)\phi(b)
\phi(1R) = 1S


The Attempt at a Solution

 
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So why is that difficult for you? You have to show an attempt or state what is confusing you before anyone can help.
 
so i have to find every set in Z that satisfies those equations by ending in Z?
same goes for Z_2 to Z_6 find every set that will add together in the homomorphism in Z_2 and will separately add together in Z_6? is this what its asking?
if so how do i show that?
 
Your definition says phi(1)=1. Can you use that with the other homomorphism properties to figure out what phi(k) must be for the other k's in the domain ring?
 
A journey of infinite length starts with a single step... :smile:
 
Z6 \rightarrow Z2 \phi(a mod 6) = a mod 2. since if a \equivb mod 6 then a\equivbmod 2 since 2|6
 
The answer is correct. But I can't say the reason really captures the what the problem is about.
 
Z_2 only has two members. Z6[/sup] only has 6 members. It shouldn't be all that hard to write down all functions from Z2 to Z6 much less just all homomorphims were you know 0Z2---> 0Z6!
 
Z is the initial object of category of rings with morphism f:Z->S satisfying f(1z) = 1s (1z is the mulitplicative identity of Z and 1s is the multiplicative identity of a ring S.

That means, a ring homomorphism f from Z to any ring is unique as long as f:Z->S satisfying f(1z) = 1s.
 
Last edited:
  • #10
Dick said:
The answer is correct. But I can't say the reason really captures the what the problem is about.

frankly I don't really care about capturing the reason of the problem. I just need to get through this class and not have a W on my transcript. Abstract math and modern algebra are terrible awful aspects of math that i just can't grasp.
so as long as that is something i can put down and get credit for I don't care, I'll never have to do it again
 

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