How Do You Find the k-th Derivative of a Polynomial at x=0?

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Homework Statement


Consider the following polynomial of degree n > 1,
P(x) = anxn + an¡1xn¡1 + ¢ ¢ ¢ + a1x + a0;
where a0; : : : ; an are some non-zero constants (don't give them values!).


Homework Equations



a. We know that P0(x) = nanxn¡1+(n¡1)anxn¡2+¢ ¢ ¢+2a2x+a1, and then P0(0) = a1. Keep
di®erentiating and ¯nd a formula for P(k)(0), the k-th derivative of P at x = 0, for k = 1; : : : ; n.
Recall that the factorial of n is de¯ned as n! := 1 £ ¢ ¢ ¢ £ (n ¡ 1) £ n, 0! := 1.
b. Consider f(x) = ex. Find the polynomial P of degree n that \best approximates" f around
x = 0. That is, use the result in part a to ¯nd a0; a1; : : : an in the formula of P, such that:
f(0) = P(0); f0(0) = P0(0); f00(0) = P00(0); : : : ; f(n)(0) = P(n)(0):
c. Use P to give an approximate formula for the number e. This is the n-th order approximation
to e.

The Attempt at a Solution



I don't even know how to begin this. SO if someone could give me some clues as to how to do this
 
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Welcome to PF luju.
Unfortunately your post is not very readable. Do you know a little bit about LaTeX? Then you can just [ t e x ] and [ / t e x ] tags (remove all the spaces from the tags) to use TeX code to make it clearer. Otherwise, please try to use only basic ASCII characters, without stuff like ¡ £ ¢

For a: Just start as the question suggests: differentiate the polynomial. And differentiate again. And again ...
For b: What do you know about the function e^x and its derivatives? What restrictions does this give on the derivatives you found in a) ?
For c, you should finish a and b first.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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