How Do You Integrate Cosine Powers in Calculus?

[golanor]

Homework Statement

\int { { cos }^{ 2n+1 }(x)dx }

Homework Equations

{ cos }^{ 2 }+{ sin }^{ 2 } = 1

The Attempt at a Solution

i got to here:
\int { { (1-{ sin }^{ 2 }(x)) }^{ n }d(sin(x)) }

Any help would be appreciated!

 

[micromass]

So you got to find

\int (1-x^2)^ndx.

Use the binomial theorem and linearity of the integral.

 

[Ray Vickson]

Homework Statement

\int { { cos }^{ 2n+1 }(x)dx }

Homework Equations

{ cos }^{ 2 }+{ sin }^{ 2 } = 1

The Attempt at a Solution

i got to here:
\int { { (1-{ sin }^{ 2 }(x)) }^{ n }d(sin(x)) }

Any help would be appreciated!

There is no simple formula for the result, unless you want to express it in terms of a hypergeometric function. The answer is a polynomial of degree (2n+1) in $\sin(x)$.

BTW: in [t e x] you should write "\sin(x)" instead of "sin(x)": the difference is $\sin(x)$ (nice) vs. $sin(x)$ (not nice).

 

[golanor]

There is no simple formula for the result, unless you want to express it in terms of a hypergeometric function. The answer is a polynomial of degree (2n+1) in $\sin(x)$.

BTW: in [t e x] you should write "\sin(x)" instead of "sin(x)": the difference is $\sin(x)$ (nice) vs. $sin(x)$ (not nice).

Thanks for the tex hint..still getting the hang of it (used to microsoft equation editor =\)

So you got to find

\int (1-x^2)^ndx.

Use the binomial theorem and linearity of the integral.

Thanks, i actually read about it, thought that i should use it but decided not to.

In case anyone wants the answer, it is:
\int { { (1-{ \sin }^{ 2 }(x)) }^{ n }d(\sin (x)) } =\sin (x)-\frac { n{ \sin }^{ 3 }(x) }{ 3 } +...+\frac { { (-1) }^{ n }{ \sin }^{ 2n+1 }(x) }{ 2n+1 } +C